WB JEE Medical WB JEE Medical Solved Paper-2007

  • question_answer
    Figure below shows four plates each of area A and separated from one another by a distance d.  What is the capacitance between P and Q?

    A)  \[\frac{{{\varepsilon }_{0}}A}{d}\]                         

    B)  \[\frac{2{{\varepsilon }_{0}}A}{d}\]

    C)  \[\frac{3{{\varepsilon }_{0}}A}{d}\]                       

    D)  \[\frac{4{{\varepsilon }_{0}}A}{d}\]

    Correct Answer: B

    Solution :

                     Two capacitors (in parallel order) are formed between the plates. So,       \[{{C}_{PQ}}={{C}_{1}}+{{C}_{2}}\]                 \[=\frac{A{{\varepsilon }_{0}}}{d}+\frac{A{{\varepsilon }_{0}}}{d}=\frac{2A{{\varepsilon }_{0}}}{d}\]


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