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WB JEE Medical WB JEE Medical Solved Paper-2007

  • question_answer
    A soap bubble is charged to a potential of 16 V. Its radius is, then doubled. The potential of the bubble now will be

    A)  16 V                                     

    B)  8 V

    C)  4 V                                        

    D)  2 V

    Correct Answer: B

    Solution :

                     Potential on bubble, \[V=\frac{1}{4\pi {{\varepsilon }_{0}}}\frac{q}{r}\] \[\therefore \]  \[\frac{{{V}_{1}}}{{{V}_{2}}}=\frac{{{r}_{2}}}{{{r}_{1}}}\] \[\Rightarrow \]               \[\frac{16}{{{V}_{2}}}=\frac{2}{1}\] \[\Rightarrow \]               \[{{V}_{2}}=8\,V\]


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