A) 8:1
B) 1 : 8
C) 2:1
D) 1:2
Correct Answer: A
Solution :
Given, \[{{Q}_{1}}=10\,unit,{{Q}_{2}}=-20\,unit\] After contact charges on both become same, ie, \[Q=\frac{10-20}{2}=-5\,\text{units}\] \[\therefore \] \[|{{F}_{1}}|\,=\,\frac{1}{4\pi {{\varepsilon }_{0}}}\times \frac{10\times 20}{{{r}^{2}}}\] and \[|{{F}_{2}}|\,=\frac{1}{4\pi {{\varepsilon }_{0}}}\times \frac{5\times 5}{{{r}^{2}}}\] Hence, \[\frac{|{{F}_{1}}|}{|{{F}_{2}}|}=\frac{8}{1}\]You need to login to perform this action.
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