WB JEE Medical WB JEE Medical Solved Paper-2007

  • question_answer
    A milliammeter of range 0 - 30 mA has  internal  resistance of \[20\,\Omega .\] The resistance to be connected in series to convert it into a voltmeter of maximum reading 3V is

    A)  490                                       

    B)  800

    C)  400                                       

    D)  300

    Correct Answer: B

    Solution :

                     \[R=\frac{V}{{{I}_{g}}}-G\] \[=\frac{3}{30\times {{10}^{-3}}}-20={{10}^{2}}-20\] \[=80\,\Omega \]


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