A) \[\frac{{{\pi }^{2}}I}{l}\times {{10}^{-7}}\]
B) \[\frac{\pi I}{l}\times {{10}^{-7}}\]
C) \[\frac{\pi I}{{{l}^{2}}}\times {{10}^{-7}}\]
D) \[\frac{\pi {{I}^{2}}}{l}\times {{10}^{-7}}\]
Correct Answer: A
Solution :
Radius, \[r=\frac{1}{\pi }\] Magnetic field at the centre, \[B=\frac{{{\mu }_{0}}I}{4r}\] \[=\frac{4\pi \times {{10}^{-7}}\times I}{4\times \frac{l}{\pi }}\] \[=\frac{{{\pi }^{2}}I\times {{10}^{-7}}}{l}\]
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