A) 141V, 628 Hz
B) 100 V, 50 Hz
C) 100 V, 100 Hz
D) 141 V, 100 Hz
Correct Answer: C
Solution :
\[E=141\sin 628\,t\] \[\therefore \] \[{{E}_{rms}}=\frac{{{E}_{0}}}{\sqrt{2}}\] \[=\frac{141}{1.41}=100\,V\] and \[v=\frac{\omega }{2\pi }\] \[=\frac{628}{2\times 3.14}=100\,Hz\]
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