A) \[-\frac{1}{3}\frac{d[A]}{dt}\]
B) \[-\frac{2}{3}\frac{d[A]}{dt}\]
C) \[+\frac{2d[A]}{dt}\]
D) \[-\frac{3}{2}+\frac{d[A]}{dt}\]
Correct Answer: B
Solution :
For the reaction, \[3A\xrightarrow{{}}2B\] \[\text{Rate}=-\frac{1}{3}\frac{d[A]}{dt}=+\frac{1}{2}\frac{d[B]}{dt}\] \[\therefore \] \[+\frac{d[B]}{dt}=-\frac{2}{3}\frac{d[A]}{dt}\]You need to login to perform this action.
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