A) \[_{56}^{141}Sr\]
B) \[_{56}^{141}La\]
C) \[_{56}^{141}Ba\]
D) \[_{56}^{141}Cs\]
Correct Answer: C
Solution :
The complete nuclear reaction is\[_{92}^{235}U+{{\,}_{0}}{{n}^{1}}\xrightarrow{{}}_{56}^{141}Ba+_{36}^{92}Kr+3_{0}^{1}n\]You need to login to perform this action.
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