A) \[M{{e}_{2}}C=CHMe\]
B) \[M{{e}_{2}}C=CM{{e}_{2}}\]
C) \[MeC{{H}_{2}}-C(Me)=CM{{e}_{2}}\]
D) \[MeCH(Me)-CH=CHMe\]
Correct Answer: A
Solution :
\[\xrightarrow{Zn/C{{H}_{3}}COOH}\underset{\text{ketone}}{\mathop{Me-\overset{O}{\mathop{\overset{|\,\,|}{\mathop{C}}\,}}\,-}}\,Me+\underset{\text{aldehyde}}{\mathop{Me-\overset{O}{\mathop{\overset{|\,\,|}{\mathop{C}}\,}}\,-H}}\,\]You need to login to perform this action.
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