A) \[f\]
B) \[2f\]
C) \[f/2\]
D) \[f/4\]
Correct Answer: A
Solution :
(i) Here, \[\frac{\lambda }{2}=l\Rightarrow \lambda =2l\] So, \[v=\frac{v}{2l}\] (ii) and \[\frac{\lambda }{4}=\frac{l}{2}\] \[\lambda =\frac{4l}{2}=2l\] \[\therefore \] \[{{v}_{2}}=\frac{v}{2l},\]the same \[\therefore \]\[f\] (original) is the frequencyYou need to login to perform this action.
You will be redirected in
3 sec