A) \[C{{H}_{2}}BrC{{H}_{2}}Br\]
B) \[CB{{r}_{3}}C{{H}_{3}}\]
C) \[CHBr=CHBr\]
D) \[CB{{r}_{2}}=C{{H}_{2}}\]
Correct Answer: C
Solution :
Due to restricted rotation about double bond, the alkene shows geometrical isomerism because the relative position of atoms or groups attached to the carbon atoms of the double bond get fixed. If same group or atom attached with double bond bearing carbon, then alkene doesnt show geometrical isomerism.
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