A) \[s{{p}^{3}}\]
B) \[{{d}^{3}}s\]
C) \[s{{p}^{2}}f\]
D) \[ds{{p}^{2}}\]
Correct Answer: D
Solution :
Cu-ammonia complex is \[{{[Cu{{(N{{H}_{3}})}_{4}}]}^{2+}}\] \[\text{N}{{\text{H}}_{\text{3}}}\]being strong field ligand, shifts the unpaired electron to higher level.You need to login to perform this action.
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