question_answer

The force F acting on a particle moving in a straight line is shown below. What is the work done by the force on the particle in the 1st metre of the trajectory?

A)  5 J                                         

B)  10 J

C)  15 J                                       

D)  2.5 J

Correct Answer: D

Solution :

                  Work done = Area of triangle ABC \[=\frac{1}{2}\times 1\times 5\] \[=2.5\,J\]