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WB JEE Medical WB JEE Medical Solved Paper-2009

  • question_answer
    A particle is projected at \[\text{6}{{\text{0}}^{\text{o}}}\] to the horizontal with a kinetic energy KE. The kinetic energy at the highest point is

    A)  KE                                         

    B)  Zero

    C)  \[\frac{KE}{4}\]                                               

    D)  \[\frac{KE}{2}\]

    Correct Answer: C

    Solution :

                     Let initial velocity of the particle be v. \[\therefore \]  \[KE=\frac{1}{2}m{{v}^{2}}\] at the highest point of its flight \[v=u\cos {{60}^{o}}=\frac{u}{2}\] \[\therefore \] Kinetic energy at this point \[=\frac{1}{2}m{{v}^{2}}=\frac{1}{2}\frac{m{{u}^{2}}}{4}=\frac{KE}{4}\]


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