A) \[1\,erg\]
B) \[1\,J\]
C) \[1\,eV\]
D) \[1\,MeV\]
Correct Answer: A
Solution :
Frequency of one photon \[=2500{{s}^{-1}}\] \[\therefore \] Frequency of 1 mole of photon \[=6.023\times {{10}^{23}}\times 2500\,{{s}^{-1}}\] Total energy of 1 mole of photon, \[E=hv\] \[=6.626\times {{10}^{-34}}Js\times 6.023\times {{10}^{23}}\times 2500\,{{s}^{-1}}\] \[=9.97\times {{10}^{-7}}\,J\approx 10\,erg\] In option there should be 10 erg instead of 1 erg.You need to login to perform this action.
You will be redirected in
3 sec