A) 0
B) 1
C) 2
D) 3
Correct Answer: C
Solution :
Half-life period \[{{t}_{1/2}}\propto \frac{1}{a_{0}^{n-1}}\] ?.(i) where, \[{{a}_{0}}=\]initial concentration and \[n=\]order of reaction since graph between \[{{t}_{1/2}}\]and \[\frac{1}{{{a}_{0}}}\] is a straight line, \[{{t}_{1/2}}\propto \frac{1}{{{a}_{0}}}\] ?(ii) From Eq (i) and (ii), \[\Rightarrow \] \[\frac{1}{a_{0}^{n-1}}=\frac{1}{{{a}_{0}}}\] or \[n-1=1\] \[\therefore \] \[n=2\] Hence, the reaction is of second order.You need to login to perform this action.
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