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WB JEE Medical WB JEE Medical Solved Paper-2009

  • question_answer
    The distance between an object and a divergent lens is m times the focal length of the lens. The linear magnification produced by the lens is

    A)  \[m\]                                   

    B)   \[\frac{1}{m}\]

    C)  \[m+1\]                              

    D)  \[\frac{1}{m+1}\]           

    Correct Answer: D

    Solution :

                     Given, \[u=-mf\] \[\therefore \]  \[\frac{1}{v}-\frac{1}{(-mf)}=-\frac{1}{f}\] \[\Rightarrow \]               \[\frac{1}{v}=-\frac{1}{f}\left( 1+\frac{1}{m} \right)\]      \[\Rightarrow \]               \[-\frac{v}{f}=\frac{m}{m+1}\] \[\Rightarrow \]               \[-\frac{v}{u}=\left( \frac{1}{1+m} \right)\]


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