A) \[4200\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
B) \[5800\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
C) \[4150\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
D) \[3150\,\overset{\text{o}}{\mathop{\text{A}}}\,\]
Correct Answer: D
Solution :
Wavelengh \[\lambda \propto \frac{1}{\mu }\] \[\therefore \] \[\frac{{{\lambda }_{2}}}{{{\lambda }_{1}}}=\frac{{{\mu }_{1}}}{{{\mu }_{2}}}=\frac{3}{4}\] \[\left( \because \,{{\,}_{1}}{{\mu }_{2}}=\frac{4}{3} \right)\] or \[{{\lambda }_{2}}=\frac{3}{4}{{\lambda }_{1}}=\frac{3}{4}\times 4200=3150\overset{\text{o}}{\mathop{\text{A}}}\,\]
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