A) \[10\,m{{s}^{-1}}\]
B) \[18\,m{{s}^{-1}}\]
C) \[14\,m{{s}^{-1}}\]
D) \[26\,m{{s}^{-1}}\]
Correct Answer: C
Solution :
Given \[a=3t+4\] \[\Rightarrow \] \[\frac{dv}{dt}=3t+4\] \[\therefore \] \[\int_{0}^{v}{dv}=\int_{0}^{t}{(3t+4)dt}\] \[\Rightarrow \] \[v=\frac{3}{2}{{t}^{2}}+4t\] at \[t=2s\] \[v=\frac{3}{2}{{(2)}^{2}}+4(2)=14m{{s}^{-1}}\]You need to login to perform this action.
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