A) \[5\times {{10}^{29}}\]
B) \[12.5\times {{10}^{18}}\]
C) \[1.6\times {{10}^{19}}\]
D) \[9\times {{10}^{11}}\]
Correct Answer: B
Solution :
Charge \[q=ne\] \[\therefore \] \[n=\frac{q}{e}=\frac{2}{1.6\times {{10}^{-19}}}=12.5\times {{10}^{18}}\]
You need to login to perform this action.
You will be redirected in
3 sec
