WB JEE Medical WB JEE Medical Solved Paper-2009

  • question_answer
    If the charge on a capacitor is increased by 2 coulomb, the energy stored in it increases by 21%. The original charge on the capacitor is

    A)  10C                                       

    B)  20C

    C)  30C                                       

    D)  40C

    Correct Answer: B

    Solution :

                     According to question \[\frac{\frac{q_{f}^{2}}{2C}-\frac{q_{i}^{2}}{2C}}{\frac{q_{i}^{2}}{2C}}\times 100=21\]and \[{{q}_{f}}-{{q}_{i}}=2\] Solving, we get \[{{q}_{i}}=20C.\]


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