A) \[\text{0}{{\,}^{\text{o}}}\text{C}\]
B) \[-\text{5}{{\,}^{\text{o}}}\text{C}\]
C) \[\text{5}{{\,}^{\text{o}}}\text{C}\]
D) \[10{{\,}^{\text{o}}}\text{C}\]
Correct Answer: C
Solution :
Let the final temperature of mixture be \[\text{t}{{\,}^{\text{o}}}\text{C}\text{.}\]Heat lost by water in calories, \[{{\text{H}}_{1}}=19\times 1\times (30-t)\] \[=570-19t\] Heat taken by ice, \[{{H}_{2}}=m{{s}_{i}}\Delta t+mL+m{{s}_{w}}t\] \[=5\times (0.5)20+5\times 80+5\times 1\times t\] According to principle of calorimetry, \[{{H}_{1}}={{H}_{2}}\] \[5\times (0.5)\times 20+5\times 80+5t=570-19t\] \[\Rightarrow \] \[24t=570-450=120\] \[\Rightarrow \] \[t=5{{\,}^{o}}C\]You need to login to perform this action.
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