A) \[m\]
B) \[\frac{1}{m}\]
C) \[m+1\]
D) \[\frac{1}{m+1}\]
Correct Answer: D
Solution :
Given, \[u=-mf\] \[\therefore \] \[\frac{1}{v}-\frac{1}{(-mf)}=-\frac{1}{f}\] \[\Rightarrow \] \[\frac{1}{v}=-\frac{1}{f}\left( 1+\frac{1}{m} \right)\] \[\Rightarrow \] \[-\frac{v}{f}=\frac{m}{m+1}\] \[\Rightarrow \] \[-\frac{v}{u}=\left( \frac{1}{1+m} \right)\]You need to login to perform this action.
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