A) \[\frac{qQ}{4\pi {{\varepsilon }_{0}}r}\]
B) \[\frac{qQ}{4\pi {{\varepsilon }_{0}}}\frac{1}{\pi r}\]
C) \[\frac{qQ}{4\pi {{\varepsilon }_{0}}}\left( \frac{1}{2\pi r} \right)\]
D) zero
Correct Answer: D
Solution :
Since electrostatic force is conservative force, therefore work done by this conservative force in a round trip is zero.
You need to login to perform this action.
You will be redirected in
3 sec
