A) \[\frac{r}{I}\] oersted
B) \[\frac{2\pi I}{r}\] oersted
C) \[\frac{I}{2\pi r}\] oersted
D) \[\frac{2\pi r}{I}\] oersted
Correct Answer: B
Solution :
\[H=\frac{{{\mu }_{0}}I}{2r}=\frac{{{\mu }_{0}}}{4\pi }\times \frac{2\pi I}{r}\] In emu system \[\frac{{{\mu }_{0}}}{4\pi }=1\] So, \[H=\frac{2\pi I}{r}\]oersted
You need to login to perform this action.
You will be redirected in
3 sec
