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WB JEE Medical WB JEE Medical Solved Paper-2009

  • question_answer
    1 mole of photon, each of frequency \[2500{{s}^{-1}},\] would have approximately a total energy of

    A) \[1\,erg\]                                           

    B)  \[1\,J\]

    C)  \[1\,eV\]                                           

    D)  \[1\,MeV\]

    Correct Answer: A

    Solution :

                     Frequency of one photon \[=2500{{s}^{-1}}\] \[\therefore \] Frequency of 1 mole of photon \[=6.023\times {{10}^{23}}\times 2500\,{{s}^{-1}}\] Total energy of 1 mole of photon, \[E=hv\] \[=6.626\times {{10}^{-34}}Js\times 6.023\times {{10}^{23}}\times 2500\,{{s}^{-1}}\] \[=9.97\times {{10}^{-7}}\,J\approx 10\,erg\] In option there should be 10 erg instead of 1 erg.


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