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WB JEE Medical WB JEE Medical Solved Paper-2009

  • question_answer
    The following graph shows how \[{{t}_{1/2}}\] (half-life) of a reactant, R changes with the initial reactant concentration \[{{a}_{0}}.\] The order of the reaction will be

    A)  0                                            

    B)  1

    C)  2                                            

    D)  3

    Correct Answer: C

    Solution :

                     Half-life period \[{{t}_{1/2}}\propto \frac{1}{a_{0}^{n-1}}\]                        ?.(i) where, \[{{a}_{0}}=\]initial concentration and \[n=\]order of reaction since graph between \[{{t}_{1/2}}\]and \[\frac{1}{{{a}_{0}}}\] is a straight line, \[{{t}_{1/2}}\propto \frac{1}{{{a}_{0}}}\]                                                               ?(ii) From Eq (i) and (ii), \[\Rightarrow \]               \[\frac{1}{a_{0}^{n-1}}=\frac{1}{{{a}_{0}}}\] or            \[n-1=1\] \[\therefore \]  \[n=2\] Hence, the reaction is of second order.


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