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WB JEE Medical WB JEE Medical Solved Paper-2009

  • question_answer
    The equilibrium constant (K) of a reaction may be written as

    A)  \[K={{e}^{-\Delta G/RT}}\]                        

    B)  \[K={{e}^{-\Delta {{G}^{o}}/RT}}\]

    C)  \[K={{e}^{-\Delta H/RT}}\]                         

    D)  \[K={{e}^{-\Delta {{H }^{o}}/RT}}\]

    Correct Answer: B

    Solution :

                     Gibbs free energy \[(\Delta {{G}^{o}})\] is related with equilibrium constant \[(K)\]as \[\Delta {{G}^{o}}=-RT\ln K\] \[-\frac{\Delta {{G}^{o}}}{RT}=\ln \,K\] \[\therefore \]  \[K={{e}^{\frac{-\Delta {{G}^{o}}}{RT}}}\]


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