A) 40 min
B) 60 min
C) 30 min
D) 50 min
Correct Answer: A
Solution :
When the reaction is 10% completed, \[k=\frac{2.303}{20}\log \frac{100}{100-10}\] ?(i) When the reaction is 19% completed, \[k=\frac{2.303}{t}\log \frac{100}{100-19}\] ?(ii) From Eq (i) and (ii), \[\Rightarrow \] \[\frac{2.303}{20}\log \frac{100}{90}=\frac{2.303}{t}\log \frac{100}{81}\] \[\Rightarrow \] \[\frac{1}{20}\times 0.04575=\frac{1}{t}\times 0.09151\] \[\therefore \] \[t=40\,\min .\]You need to login to perform this action.
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