A) \[\lambda =\frac{5}{3R}\]
B) \[\lambda =\frac{4}{3R}\]
C) \[\lambda =\frac{R}{4}\]
D) \[\lambda =\frac{3R}{4}\]
Correct Answer: B
Solution :
\[\frac{1}{\lambda }=R\left( \frac{1}{n_{2}^{2}}-\frac{1}{n_{1}^{2}} \right)\] \[=R\left( \frac{1}{{{1}^{2}}}-\frac{1}{{{2}^{2}}} \right)=\frac{3R}{4}\] \[\Rightarrow \] \[\lambda =\frac{4}{3R}\]You need to login to perform this action.
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