The force F acting on a particle moving in a straight line is shown below. What is the work done by the force on the particle in the 1st metre of the trajectory?
A) 5 J
B) 10 J
C) 15 J
D) 2.5 J
Correct Answer:
D
Solution :
Work done = Area of triangle ABC \[=\frac{1}{2}\times 1\times 5\] \[=2.5\,J\]