A) fuming \[{{H}_{2}}S{{O}_{4}}\]
B) pyrogallol
C) ammoniacal\[C{{u}_{2}}C{{l}_{2}}\]
D) charcoal powder
Correct Answer: C
Solution :
\[CH\equiv CH+C{{u}_{2}}C{{l}_{2}}(ammoniacal)\to \underset{\begin{smallmatrix} \text{copper}\,\text{acetylide} \\ \,\,\,\,\,\,\,\,\,\,\,\,\text{(red}\,\text{ppt)} \end{smallmatrix}}{\mathop{CuC\equiv CCu}}\,\]\[C{{H}_{2}}=C{{H}_{2}}+C{{u}_{2}}C{{l}_{2}}(ammoniacal)\xrightarrow{{}}\] \[\times \,(no\,reaction)\] \[\therefore \] Ammoniacal \[\text{C}{{\text{u}}_{\text{2}}}\text{C}{{\text{l}}_{\text{2}}}\]is used to separate ethylene from acetylene.
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