A) \[{{K}_{2}}C{{r}_{2}}{{O}_{7}}/{{H}_{2}}S{{O}_{4}}\]
B) \[Zn-Hg/HCl\]
C) \[Se{{O}_{2}}\]
D) Iodine/NaOH
Correct Answer: D
Solution :
Ketones having \[C{{H}_{3}}CO-\]group give yellow coloured iodoform with \[{{I}_{2}}\] and NaOH. \[\underset{2-\text{pentanone}}{\mathop{C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}\overset{O}{\mathop{\overset{|\,\,|}{\mathop{C}}\,C{{H}_{3}}}}\,}}\,+{{I}_{2}}+NaOH\xrightarrow{{}},\] \[\underset{\text{iodoform}}{\mathop{CH{{I}_{3}}}}\,+C{{H}_{3}}C{{H}_{2}}C{{H}_{2}}COONa+NaI+{{H}_{2}}O\] \[C{{H}_{3}}C{{H}_{2}}\overset{O}{\mathop{\overset{|\,\,|}{\mathop{C}}\,}}\,C{{H}_{2}}{{H}_{3}}+{{I}_{2}}+NaOH\to \] No reaction \[\therefore \]\[{{I}_{2}}/NaOH\]is used to distinguish between 2-pentanone and 3-pentanone.
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