A) 2
B) 4
C) 3
D) 5
Correct Answer: A
Solution :
During alcoholic fermentation of glucose molecule, pyruvic add is first decarboxylated to form acetaldehyde and \[C{{O}_{2}},\] which is then changed to ethyl alcohol with the help of NADH. Net gain is 2ATP molecules per glucose molecule. \[\begin{align} & {{C}_{6}}{{H}_{12}}{{O}_{6}}+\,2ADP\,+\,2Pi\xrightarrow[{}]{{}}2{{C}_{2}}{{H}_{5}}OH \\ & Glu\cos e\,Ethyl\,alcohol \\ & +\,2C{{O}_{2}}\,+\,2ATP\,+\,2{{H}_{2}}O \\ \end{align}\]
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