A) 1.17
B) 1.0
C) 0.3
D) log 2-log 3
Correct Answer: B
Solution :
Millimoles of \[{{H}^{+}}=0.1\times 2+0.1\times 2\times 2=0.6\] Total volume in mL = 6 \[pH=-{{\log }_{10}}[{{H}^{+}}]=-\log \left( \frac{0.6}{6} \right)=-\log 0.1=1\]You need to login to perform this action.
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