Two blocks of 2 kg and 1 kg are in contact on a frictionless table. If a force of 3 N is applied on 2 kg block, then the force of contact between the two blocks will be
A) zero
B) 1 N
C) 2N
D) 3N
Correct Answer:
B
Solution :
Acceleration of both the blocks taken together \[=\frac{3}{[2+1]}=m/{{s}^{2}}.\] Hence, the contact force between the two blocks is equal to \[1\,kg\,\times 1m/{{s}^{2}}=1N\]