question_answer

Two blocks of 2 kg and 1 kg are in contact on a frictionless table. If a force of 3 N is applied on 2 kg block, then the force of contact between the two blocks will be

A)  zero                                     

B)  1 N

C)  2N                                        

D)  3N

Correct Answer: B

Solution :

                 Acceleration of both the blocks taken together \[=\frac{3}{[2+1]}=m/{{s}^{2}}.\] Hence, the contact force between the two blocks is equal to \[1\,kg\,\times 1m/{{s}^{2}}=1N\]