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WB JEE Medical WB JEE Medical Solved Paper-2010

  • question_answer
    The height vertically above the earths surface at which the acceleration due to gravity becomes 1% of its value at the surface is (R is the radius of the earth)

    A)  8R                                         

    B)  9R

    C)  10R                                       

    D)  20R

    Correct Answer: B

    Solution :

                     The acceleration due to gravity varies with height as \[g=\frac{g}{{{\left( 1+\frac{h}{R} \right)}^{2}}}\]                 \[\Rightarrow \]               \[\frac{g}{100}=\frac{g}{{{\left( 1+\frac{h}{R} \right)}^{2}}}\] \[\Rightarrow \]               \[{{\left( 1+\frac{h}{R} \right)}^{2}}=100\] \[\Rightarrow \]               \[h=9R\]


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