A) \[dG=Vdp-SdT\]
B) \[dE=pdV+TdS\]
C) \[dH=-Vdp+TdS\]
D) \[dG=Vdp+SdT\]
Correct Answer: A
Solution :
\[dG=dH-TdS-SdT(as\,G=H-TS)\] Again, \[H=E+pV\] \[\therefore \] \[dH=dE+pdV+Vdp\] and \[dE=TdS-pdV\] Thus, \[dG=(TdS-pdV)+pdV+Vdp-TdS-SdT\] \[=Vdp-SdT\]You need to login to perform this action.
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