A) 2
B) -2
C) 3
D) -3
Correct Answer: C
Solution :
For two vectors\[\vec{a}\] and \[\vec{b}\]to be perpendicular, \[\vec{a}.\vec{b}=0.\] Thus, \[(5\hat{i}+\lambda \hat{j}+\hat{k}).(\hat{i}-2\hat{j}+\hat{k})\] \[=5(\hat{i}.\hat{i})-2\lambda (\hat{j}.\hat{j})+1(\hat{k}.\hat{k})\] \[0=5-2\lambda +1\] \[\Rightarrow \] \[0=6-2\lambda \Rightarrow \lambda =3\]You need to login to perform this action.
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