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WB JEE Medical WB JEE Medical Solved Paper-2010

  • question_answer
    The equation of a progressive wave is \[y=4\sin (4\pi t-0.04x+\pi /3)\]where \[x\]is in metre and t is in second. The velocity of the wave is

    A)  \[100\pi m/s\]                 

    B)  \[50\pi \,m/s\]

    C)  \[25\pi \,m/s\]                

    D)  \[\pi \,m/s\]

    Correct Answer: A

    Solution :

                     The equation of the progressive wave is given as, \[y=4\sin (4\pi -0.04x+\pi /3).\]  The velocity of the wave would be equal to                                 \[\frac{\omega }{k}=\frac{4\pi }{0.04}=100\pi \,m/s\]


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