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WB JEE Medical WB JEE Medical Solved Paper-2010

  • question_answer
    Which of the following thermodynamic relation is correct?

    A)  \[dG=Vdp-SdT\]             

    B)  \[dE=pdV+TdS\]

    C)  \[dH=-Vdp+TdS\]          

    D)  \[dG=Vdp+SdT\]

    Correct Answer: A

    Solution :

                     \[dG=dH-TdS-SdT(as\,G=H-TS)\] Again,   \[H=E+pV\] \[\therefore \]                  \[dH=dE+pdV+Vdp\] and        \[dE=TdS-pdV\] Thus, \[dG=(TdS-pdV)+pdV+Vdp-TdS-SdT\] \[=Vdp-SdT\]


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