A) \[n\beta \]
B) \[\frac{\beta }{n+1}\]
C) \[\frac{\beta }{n-1}\]
D) \[\frac{\beta }{n}\]
Correct Answer: D
Solution :
The fringe width decreases when the arrangement is placed in a liquid of refractive index n, so the final fringe width becomes \[\frac{B}{n}.\]
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