A) \[{{S}^{-1}}\]
B) \[S{{i}^{2-}}\]
C) \[{{P}^{3-}}\]
D) \[{{S}^{2-}}\]
Correct Answer: D
Solution :
\[16\,p\]means \[Z=16\]\[18{{e}^{-}}\]means 2 unit negative charge is present. Hence, species is \[{{S}^{2-}}.\]
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