A) propane
B) pentane
C) 150-pentane
D) neo-pentane
Correct Answer: D
Solution :
Neo pentane\[C{{H}_{3}}-\underset{C{{H}_{3}}}{\overset{C{{H}_{3}}}{\mathop{\underset{|}{\overset{|}{\mathop{C}}}\,}}}\,-C{{H}_{3}}\]contains all hydrogen atoms equivalent, so it will give only one monochord derivative on halogenation.You need to login to perform this action.
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