A) N > O > F
B) N < O < F
C) N > O < F
D) N < O > F
Correct Answer: C
Solution :
lonisation energy is the energy required to remove an electron from outer shell of an atom. Since, on moving from left to right in a period, size decreases, thus, larger amount of energy is required to remove an electron, ie, ionisation energy increases. Although the size of O atom is smaller as compared to N but the ionisation energy of N is higher. This is because in case of N, the electron is to be removed from half-filled \[2{{p}^{3}}\]orbital. Thus, the order of ionisation energy is O < N < F
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