A) \[s{{p}^{3}}d\]
B) \[ds{{p}^{3}}\]
C) \[s{{p}^{3}}{{d}^{2}}\]
D) \[{{d}^{2}}s{{p}^{3}}\]
Correct Answer: A
Solution :
In \[\text{PC}{{\text{l}}_{\text{5}}}\text{,}\]number of hybrid orbitals,\[H=\frac{1}{2}[V+x+A-C]\] [where, V = number of valence electrons X = number of monovalent atoms A and C = charge of cation or anion] \[H=\frac{1}{2}[5+5+0-0]\] \[=5\] Thus, the hybridisation is \[s{{p}^{3}}d.\]
You need to login to perform this action.
You will be redirected in
3 sec
