A) \[\frac{q}{{{\varepsilon }_{0}}}\]
B) zero
C) \[\frac{6q{{L}^{2}}}{{{\varepsilon }_{0}}}\]
D) \[\frac{q}{6{{L}^{2}}{{\varepsilon }_{0}}}\]
Correct Answer: A
Solution :
Since the charge is placed at the centre of the cube, so the electric flux lines move out equally from all sides of the cube. Thus the electric flux emerging from the cube is equal to \[\frac{q}{{{\varepsilon }_{0}}}.\]
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