A) 1250 J
B) 5000 J
C) 1000 J
D) 2500 J
Correct Answer: B
Solution :
The volume of water contained in the vessel would be equal to \[V={{l}^{3}}={{1}^{3}}{{m}^{3}}=1\,{{m}^{3}}.\]Assuming water to be pure so the density of water would be equal to \[d=1000\text{ }kg/{{m}^{3}},\]hence the mass of water contained in the vessel would be equal to m = Vd = 1000 kg. Thus, the work done would be equal to \[W=mgh=1000\times 10\times \frac{1}{2}=5000\,J\]
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