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WB JEE Medical WB JEE Medical Solved Paper-2011

  • question_answer
    If a person can throw a stone to maximum height of metre vertically, then the  maximum distance through which it can be thrown horizontally by the same person is

    A)  \[\frac{h}{2}\]                                 

    B)  \[h\]

    C)  \[2h\]                                  

    D)  \[3h\]

    Correct Answer: C

    Solution :

                     Using the equation of motion, we get \[h=\frac{{{u}^{2}}}{2g}\]                 thus,                      \[{{u}^{2}}=2gh\] So the maximum horizontal distance would   be given by                                 \[{{R}_{\max }}=\frac{{{u}^{2}}}{g}\]                      (when \[\theta ={{45}^{o}}\]) Hence \[{{R}_{\max }}=2h\]


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